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Centroid of a triangle

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The Centroid of a triangle


The centroid of a triangle is the point of intersection of the three medians of that triangle.


In the following acute triangle \(ABC\),
\(D\), \(E\) and \(F\) are the midpoints of \(AB\), \(BC\) and \(CA\).
So, \(CD\), \(AE\) and \(BF\) are the medians of this triangle.
The medians intersect at the point \(G\).
This point \(G\) is the centroid of \(△ABC\).


Midpoints Medians Centroid A centroid always lies inside the triangle. It divides each median in 2:1 ratio.

What is a median?

Note: A median is a segment that is drawn from a vertex of a triangle to the mid-point of the opposite side of that vertex. Each median of a triangle divides the triangle into two smaller triangles that have equal areas.
A triangle has three medians because it has three sides. The three medians divide the triangle into 6 smaller triangles of equal area.

Properties of a Centroid


Centroid of an Acute triangle

∠A = 30°, ∠B = 70°, ∠C = 80° AE, BF and CD are medians of △ABC. Point G is the centroid of the triangle.

Centroid of an Obtuse triangle

∠A = 110°, ∠B = 30°, ∠C = 40° AE, BF and CD are medians of △ABC. Point G is the centroid of the triangle.

Centroid of a Right triangle

∠A = 30°, ∠B = 90°, ∠C = 60° AE, BF and CD are medians of △ABC. Point G is the centroid of the triangle.

Centroid of an Equilateral triangle

∠A = ∠B = ∠C = 60° AE, BF and CD are medians of △ABC. Point G is the centroid of the triangle.

Centroid of an Isosceles triangle

∠A = ∠B = 70°, ∠C = 40° AE, BF and CD are medians of △ABC. Point G is the centroid of the triangle.

Coordinates of centroid

If coordinates of the vertices \(A\), \(B\) and \(C\) are \( (x_1, y_1) \), \( (x_2, y_2) \) and \( (x_3, y_3) \) respectively, then the coordinates of the centroid \(G\) can be calculated with the following formula: \[ G(x, y) = \left( \frac{x_1+x_2+x_3}{3}, \frac{y_1+y_2+y_3}{3}\right) \] For a triangle with vertices \(A(-30, 3)\), \(B(0, 3)\) and \(C(10, 30)\), the coordinates of the centroid \(G\) may be calculated as follows:
Here, \(x_1=-30,\; x_2=0,\; x_3=10,\; y_1=3,\; y_2=3,\; y_3=30 \)


Coordinates of centroid G =

Coordinates of the centroid \(G\): \begin{align} G(x, y) &= \left( \frac{-30 + 0 + 10}{3}, \frac{3 + 3 + 30}{3}\right)\\\\ &= \left( \frac{-20}{3}, \frac{36}{3}\right) \\\\ &= ( -6.67, 12 ) \\\\ \end{align} So the coordinates of the centroid of the above triangle is \(( -6.67, 12 )\)





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